Higher June 2019 Unit 1 Q11
11. Rearrange the following formula to make \(x\) the subject. [3]
\[\mathrm{c}x - 3 = 4x + d\]| Scheme | Marks | Comments |
|---|---|---|
| FT until 2nd error provided equivalent difficulty. | ||
| \(cx - 4x = d + 3\) or \(-\,3 - d = 4x - cx\) | B1 | Collecting \(x\) terms. |
| \(x(c - 4) = d + 3\) or \(-\,3 - d = x(4 - c)\) | B1 | Factorising. |
| \(x = (d + 3)/(c - 4)\) or \(x = (-\,3 - d)/(4 - c)\) or equivalent | B1 | Dividing. Mark final answer. |