(a) Draw the graph of the curve \(y = 2^x\) for values of \(x\) from –2 to 2. Use the graph paper below. [3]
(b) Use your graph to find the value of \(2^{1{\cdot}4}\). [1]
(c) Use your graph to solve the equation \(2^x = 1{\cdot}4\). [1]
Mark scheme (a)
Scheme
Marks
Comments
\(x\)
–2
–1
0
1
2
\(y\)
\(\frac{1}{4}\)
\(\frac{1}{2}\)
1
2
4
B1
Any 3 correct pairs of coordinates (need not be for integer values of x.) Must include one negative value of x.
Suitable choice of uniform scales through the origin, \(x\) from – 2 to 2 and \(y\) from 0 to 4, AND plotting at least 3 points correctly.
B1
FT their evaluations of \(y\) if shown (provided they do not produce a straight line). Must include one negative value of x. Tolerance for accuracy ± \(\frac{1}{2}\) a small square.
Joining with a curve.
C1
CAO. Exponential curve which passes through (-2, \(\frac{1}{4}\)), (0, 1) and (2, 4). Must not intercept x axis anywhere, including beyond the required range of x values. Tolerance for accuracy ± \(\frac{1}{2}\) a small square.
If no table or evaluations of coordinates are given (for at least 3 pairs of values, including one negative value of x), then B1 B1 may be implied by C1 or if C0, B1 B1 may be implied by 3 correctly plotted points for y = 2x (including one negative value of x).
Mark scheme (b)
Scheme
Marks
Comments
Reading from their graph for \(x = 1{\cdot}4\) \((y \approx 2{\cdot}6)\)
B1
FT ‘their curve’. (No FT for a straight line.) Tolerance for accuracy ± \(\frac{1}{2}\) a small square.
Mark scheme (c)
Scheme
Marks
Comments
Reading from their graph for \(y = 1{\cdot}4\) \((x \approx 0{\cdot}5)\)
B1
Accept an embedded answer. FT ‘their curve’. (No FT for a straight line.) Must include all relevant readings if ‘their graph’ is not one-to-one. Tolerance for accuracy ± \(\frac{1}{2}\) a small square.
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