13. The table below shows some of the values of \(y = x^2 + 4x + 5\) for values of \(x\) from –4 to 1.
\(x\)
–4
–3
–2
–1
0
1
\(y = x^2 + 4x + 5\)
5
2
2
5
(a) Complete the table by finding the value of \(y\) for \(x\) = –2 and for \(x\) = 1. [2]
(b) On the graph paper below, draw the graph of \(y = x^2 + 4x + 5\) for values of \(x\) from –4 to 1. [2]
Mark scheme (a)
Scheme
Marks
Comments
1 10
B2
B1 for each. Table takes precedence if conflicting values given.
Mark scheme (b)
Scheme
Marks
Comments
At least 4 correct plots and no incorrect plot.
P1
FT ‘their (−2,1)’ and ‘their (1,10)’ OR (−2,1) and (1,10) plotted. Allow ± ‘½ a small square’.
A smooth curve drawn through their plots.
C1
FT ‘their 6 plots’. OR a curve through the 4 given points AND (−2,1) and (1,10) Allow intention to pass through their plots. (± 1 small square horizontally or vertically.)
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