Intermediate November 2019 Unit 2 Q14
14. Calculate the length of the side MN in the triangle LMN shown below. [3]
Diagram not drawn to scale
| Scheme | Marks | Comments |
|---|---|---|
| MN = 13·5 × cos 27 | M2 | M1 for cos 27 = \(\dfrac{\text{MN}}{13{\cdot}5}\) |
| = 12(·0…) (cm) ISW | A1 | A correct and complete method (e.g. using two trigonometric relationships.) M2 MN = 12(·0..)(cm) ISW A1 |