Basic Trigonometry: WJEC GCSE Higher November 2022 Unit 2 Q5

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Higher November 2022 Unit 2 Q5

WJECHigherCurrent spec3 marksBasic Trigonometry

5. Calculate the length of the side \(YZ\) in the triangle \(XYZ\) shown below. [3]

Diagram not drawn to scale

Mark scheme

Scheme	Marks	Comments
\(YZ = \dfrac{7}{\cos 41(^\circ)}\) or \(7 \div \cos 41(^\circ)\)	M2	Award M2 for \(YZ = 7 \div \sin 49\ (\times \sin 90)\) or \(\dfrac{7\ (\times \sin 90)}{\sin 49}\) Award M1 for one of the following: \(\cos 41 = \dfrac{7}{YZ}\) \(\sin 49 = \dfrac{7}{YZ}\) \(\dfrac{YZ}{\sin 90} = \dfrac{7}{\sin 49}\).
= 9·27(…) or 9·28 (cm) or 9.3 (cm)	A1	Accept 9 (cm) from correct working. CAO.

Scheme	Marks	Comments
Correct use of ‘two-step’ method.	M2	A partial trigonometric method is M0.
= 9·27(…) or 9·28 (cm) or 9.3 (cm)	A1	Accept 9 (cm) from correct working.