Higher November 2021 Unit 2 Q11
11. The table below shows the value of \(d\) and the value of \(e\).
It also shows the degree of accuracy of each value.
| Value | Degree of accuracy |
|---|---|
| \(d = 64\) | Nearest whole number |
| \(e = 8{\cdot}6\) | 1 decimal place |
Use the formula
\[c = \frac{d^2}{e}\]
to calculate the least possible value of \(c\).
You must show all your working. [3]
| Scheme | Marks | Comments |
|---|---|---|
| \(\dfrac{63{\cdot}5^2}{8.65}\) | M2 | If many attempts are offered without a method/answer being identified, then mark the final attempt. If M2 not gained, award M1 for correct use of values \(63 \leqslant d \lt 64\) AND \(8{\cdot}6 \lt e \leqslant 8{\cdot}7\) |
| \(= 466(\cdot156\ldots)\) or 466·16 or 466·2 | A1 | Mark final answer. M2 required for A1. Fractional equivalent \(466(\cdot156\ldots) = 80645/173\) Allow this A1 for an answer of 470 only from correct unambiguous working seen. If no marks gained, award SC1 for sight of 63·5 and 8·65 used within the same calculation. |