Higher November 2019 Unit 2 Q5
5. Calculate the length of the side \(MN\) in the triangle \(LMN\) shown below. [3]
Diagram not drawn to scale
| Scheme | Marks | Comments |
|---|---|---|
| MN = 13·5 × cos 27 | M2 | M1 for cos 27 = \(\dfrac{MN}{13{\cdot}5}\) |
| = 12(·0…) (cm) ISW | A1 |
A correct and complete method (e.g. using two trigonometric relationships.) M2
MN = 12(·0..)(cm) ISW A1