Higher June 2022 Unit 2 Q10
10. The value of \(y\) is found using the formula \(y = \dfrac{t}{w}\).
\(t\) = 98, correct to 2 significant figures.
\(w\) = 0·5, correct to 1 significant figure.
Calculate the least value of \(y\).
Give your answer correct to 1 decimal place.
You must show all your working. [3]
Least value of \(y\) = ……………
| Scheme | Marks | Comments |
|---|---|---|
| \(\dfrac{97{\cdot}5}{0{\cdot}55}\) | M2 | If many attempts are offered without a method/answer being identified, then mark the final attempt. If M2 not gained, award M1 A0 for correct use of values 97·5 ≤ t < 98 and 0·5 < w ≤ 0·55. |
| = 177·3 | A1 | CAO. Must be to 1 decimal place. Mark final answer. An unsupported answer of 177·3 gains full marks. SC2 for an unsupported answer of 177·27(2727…), fractional equivalent = 1950/11 SC1 for an unsupported answer of 177 or 177·2 or for sight of 97·5 and 0·55 used within the same calculation. |