Higher November 2019 Unit 1 Q12
12. The points \(A\), \(B\), \(C\) and \(D\) lie on the circumference of a circle.
The straight line \(EDF\) is a tangent to the circle at \(D\).
\(B\widehat{A}C = x\) and \(C\widehat{D}E = 2x\), where \(x\) is measured in degrees.

Diagram not drawn to scale
Find the size of \(B\widehat{C}D\) in terms of \(x\).
Express your answer in its simplest form.
You must give a reason for each step of your solution. [4]
| Scheme | Marks | Comments |
|---|---|---|
| CAD = \(2x\) | B1 | Check diagram. (If this is the only B mark awarded, then \(2x\) marked on diagram must be unambiguous. Otherwise, ignore spurious angles on diagram.) |
| (Reason =) Alternate segment (theorem) | E1 | Dependent on B1. Allow ‘opposite segments’. Do not accept ‘alternate angles’ or ‘opposite angles’. |
| BCD = 180 – \(3x\) OR BCD = 3(60 – \(x\)) | B1 | F.T. 180 – (\(x\) + ‘their CAD’). Must be in simplest form. Mark final answer e.g. do not accept 60 – \(x\) or \(x\) = 60 |
| (Reason =) Opposite angles in a cyclic quadrilateral (add up to 180°) | E1 | If B0, E mark may be awarded provided there is a clear attempt to apply the circle theorem. |