Intermediate November 2023 Unit 1 Q7
7. In this question, you will be assessed on the quality of your organisation, communication and accuracy in writing.
The diagram below shows two shaded squares inside a larger square.
Diagram not drawn to scale
The diagram shows the area of each of the two shaded squares.
Calculate the total area of the two regions that have not been shaded.
You must show all your working. [5 + 2 OCW]
| Scheme | Marks | Comments |
|---|---|---|
| (length of small shaded square = ) √16 or equivalent OR (length of large shaded square =) √144 or equivalent | M1 | Check diagram for answers. Allow 16 ÷ 4 = 4. |
| (length of small shaded square = ) 4 (cm) | A1 | Sight of 4 or 12 implies M1. |
| (length of large shaded square = ) 12 (cm) | A1 | |
| (total area of unshaded regions =) 96 (cm2) | B2 | FT ‘their derived 4’ × ‘their derived 12’ × 2 Award B1 for one of the following:
|
| Organisation and Communication. | OC1 | For OC1, candidates will be expected to:
|
| Accuracy of writing. | W1 | For W1, candidates will be expected to:
|
Alternative method
| Scheme | Marks | Comments |
|---|---|---|
| 7. Alternative Method (find total area of square) | Check diagram for answers. | |
| (length of small shaded square = ) √16 or equivalent OR (length of large shaded square =) √144 or equivalent | M1 | Allow 16 ÷ 4 = 4 |
| (length of small shaded square = ) 4 (cm) (length of large shaded square = ) 12 (cm) | A1 A1 | Sight of 4 or 12 implies M1. |
| (total area of unshaded regions =)(4+12)2 – 16 – 144 | M1 | Note: 256 - 160 Award M1 for complete method. |
| 96 (cm2) | A1 | FT (‘their derived 4’ + ‘their derived 12’)2 – 16 – 144 |
Notes
In the original the alternative method is printed in italics (except “Allow 16 ÷ 4 = 4”). The OC1 and W1 rows apply to either method.