Higher November 2019 Paper 1 Q6
6. Shania has two pieces of ribbon.
One piece is \(5\frac{1}{4}\) metres long.
The difference between the lengths of the two pieces is \(2\frac{9}{20}\) metres.
Work out the two possible lengths of the other piece of ribbon.
Give each of your answers as a mixed number in its simplest form. [4]
| Scheme | Marks | Comments |
|---|---|---|
| \(7 + \dfrac{5}{20} + \dfrac{9}{20}\) or \(\dfrac{105}{20} + \dfrac{49}{20}\) oe; si and \(3 + \dfrac{5}{20} - \dfrac{9}{20}\) or \(\dfrac{105}{20} - \dfrac{49}{20}\) oe; si | M2 | equivalents may be decimals 5.25 + 2.45 and 5.25 – 2.45 M1 for \(5\dfrac{5}{20} + 2\dfrac{9}{20}\) oe or \(5\dfrac{5}{20} - 2\dfrac{9}{20}\) oe or 5.25 + 2.45 or 5.25 – 2.45 |
| \(7\dfrac{7}{10}\) and \(2\dfrac{4}{5}\) | A2 | CAO A1 for either or for a pair of correct, but unsimplified, answers |
| (4) |