Higher November 2018 Paper 1 Q12
12.
(a) Write 80 as a product of prime factors using index notation. [3]
(b) \[8112 = 2^4 \times 3 \times 13^2\]Find the value of the smallest square number that is a multiple of 8112. [2]
| Scheme | Marks | Comments |
|---|---|---|
| Method to find prime factors with two correct prime factors seen before the second error | M1 | |
| 2, 2, 2, 2, 5 | A1 | Ignore 1’s |
| \(2^4 \times 5\) | B1 | Implies all 3 marks |
| Scheme | Marks | Comments |
|---|---|---|
| 24 336 | B2 | B1 for \(2^4 \times 3^2 \times 13^2\) or \(8112 \times 3\) |
| (5) |