Higher June 2018 Paper 2 Q16
16. In an experiment it is found that \(C = \dfrac{2340}{B}\) and \(A = \dfrac{52}{\sqrt{B}}\).
Find the value of \(C\) when \(A = 130\). [2]
| Scheme | Marks | Comments |
|---|---|---|
| 14625 | B2 | B1 for sight of \(C = \dfrac{2340}{(52/A)^2}\) or \(C = \dfrac{2340}{(52/130)^2}\) or \(C = \dfrac{2340}{0.4^2}\) or \(B = 0.16\) |
| (2) |