Foundation June 2019 Paper 1 Q23
23.
\[\mathbf{p} = \begin{pmatrix} 4 \\ 2 \end{pmatrix} \quad \text{and} \quad \mathbf{q} = \begin{pmatrix} -3 \\ 2 \end{pmatrix}\]Work out the column vector \(\frac{1}{2}\mathbf{p} - \mathbf{q}\). [2]
\[\frac{1}{2}\mathbf{p} - \mathbf{q} = \begin{pmatrix} \phantom{00} \\ \phantom{00} \end{pmatrix}\]| Scheme | Marks | Comments |
|---|---|---|
| \(\begin{pmatrix} 5 \\ -1 \end{pmatrix}\) | B2 | Mark final answer for B2 B1 for each element or for (\(\tfrac{1}{2}\mathbf{p}\) =) \(\begin{pmatrix} 2 \\ 1 \end{pmatrix}\) oe seen or for \(\begin{pmatrix} \dfrac{5}{-1} \end{pmatrix}\) or for \(\dfrac{5}{-1}\) in working space without brackets; allow \(\dfrac{2}{1}\) seen for B1. |
| (2) |