Higher November 2024 Paper 2 Q8
8.
(a) Tiana and Kamal work at a bank.
Their hourly pay rates are different.
On Thursday, Tiana worked for six hours and Kamal worked for seven hours.
Their combined income on Thursday was £185.75.
On Friday, Tiana worked for five hours and Kamal worked for four hours.
Their combined income on Friday was £130.50.
Use an algebraic method (not trial and improvement) to calculate Tiana and Kamal’s hourly pay rates.
You must show all your working. [5]
Their hourly pay rates are different.
On Thursday, Tiana worked for six hours and Kamal worked for seven hours.
Their combined income on Thursday was £185.75.
On Friday, Tiana worked for five hours and Kamal worked for four hours.
Their combined income on Friday was £130.50.
Use an algebraic method (not trial and improvement) to calculate Tiana and Kamal’s hourly pay rates.
You must show all your working. [5]
(b) Fran also works at the bank part-time.
She earns 35% less than the full-time salary at her pay rate.
Fran’s annual part-time salary is £24 570.
What would Fran’s annual salary be if she worked full time? [3]
She earns 35% less than the full-time salary at her pay rate.
Fran’s annual part-time salary is £24 570.
What would Fran’s annual salary be if she worked full time? [3]
| Scheme | Marks | Comments |
|---|---|---|
| \(6T + 7K =\) (£)185.75 AND \(5T + 4K =\) (£)130.50 | B1 | Both equations given, T & K may be other letters, words are accepted. FT provided at least one equation is correct, the equations have consistent place value and are of an equivalent level of difficulty. |
| Method to eliminate an unknown e.g. equal coefficients and subtraction or rearranges one equation and substitutes into the other | M1 | No marks for use of T&I or for an unsupported answer. Candidates may use \(11T + 11K =\) (£)316.25 Allow one error in one term, but not in the equated coefficients |
| Finds one unknown | A1 | CAO; \(T = 15.5(0)\) or \(K = 13.25\) |
| Method to find second unknown | m1 | FT ‘their T’ or ‘their K’ used in one of their equations |
| Finds second unknown | A1 | FT |
| Scheme | Marks | Comments |
|---|---|---|
| 65 % ≡ (£)24570 | B1 | Allow for clear indication that 65 % ≡ (£)24570, not for sight of 65% or 0.65. |
| \(24570 \div 65 \times 100\) | M1 | Or equivalent e.g. \(24570 \div 0.65\) This implies B1 M1 |
| = (£)37800 | A1 | |
| (8) |