Higher June 2024 Paper 2 Q22
22. A line, L, passes through the point (–1, 5) and is perpendicular to \(y = \frac{1}{2}x + 5\).
Find the equation of the line L.
Give your answer in the form \(ax + by + c = 0\). [3]
| Scheme | Marks | Comments |
|---|---|---|
| (Gradient of the perpendicular line =) \(-2\) | B1 | May be implied in later working |
| \(5 = -2\times-1 + c\) or \((y - 5) = -2(x + 1)\) oe or \(y = -2x + 3\) | M1 | FT for gradients of 2 and \(-\frac{1}{2}\) only |
| \(2x + y - 3 = 0\) or \(-2x - y + 3 = 0\) | A1 | FT Allow \(y + 2x - 3 = 0\) oe Mark final answer Note: B0 M1 A1 for the following Gradient of 2 leading to \(2x - y + 7 = 0\) oe Gradient of \(-\frac{1}{2}\) leading to \(x + 2y - 9 = 0\) oe |
| (3) |