4400 Higher November 2006 Paper 4 Q12
12 Solve the simultaneous equations
\[6x + 5y = 5\]\[3x - 10y = 15\](3)
| Scheme | Marks |
|---|---|
| \(12x + 10y = 10\) (\(15x = 25\)) or \(6x - 20y = 30\) (\(25y = -25\)) | M1 |
| \(x = 1\frac{2}{3}\) (or 1.7 or better) | A1 |
| \(y = -1\) | A1 |
| (3) | |
| (3 marks) |
Notes
M1: Correctly equating coefficients of \(x\) or \(y\) or rearranging to \(x = \ldots\) or \(y = \ldots\)
A1: Condone 1.66
A1: cao