4MA0 Foundation January 2012 Paper 1 Q6
6 Here are some patterns made from crosses.

(a) In the space below, draw Pattern number 5 (1)
This rule can be used to find the number of crosses in each pattern.
Multiply the Pattern number by 3 and then subtract 2
(b) Work out the number of crosses in Pattern number 9 (2)
(c) A pattern has 37 crosses.
Work out the Pattern number. (2)
Work out the Pattern number. (2)
(d) \(N\) is the number of crosses in Pattern number \(P\).
Write down a formula for \(N\) in terms of \(P\). (3)
Write down a formula for \(N\) in terms of \(P\). (3)
| Scheme | Marks |
|---|---|
![]() | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| 9 × 3 – 2 | M1 |
| 25 | A1 |
| (2) |
| Scheme | Marks |
|---|---|
| (37 + 2) ÷ 3 or 37 = 3“n” – 2 | M1 |
| 13 | A1 |
| (2) |
Notes
M1: accept ÷3 and +2 operating on 37 in any order (e.g 14.33...)
| Scheme | Marks |
|---|---|
| \(N = 3P - 2\) | B3 |
| (3) | |
| (Total 8 marks) |
Notes
B3: B3 for \(N = 3P - 2\) oe
B2 for \(3P - 2\)
B1 for \(N =\) linear function of \(P\)
