4MA0 Higher January 2017 Paper 4R Q8
8 The diagram shows a parallelogram \(ABCD\).
Diagram NOT accurately drawn
Angle \(BAD = (7x - 20)°\)
Angle \(ADC = (160 - 3x)°\)
Work out the value of \(x\).
Show clear algebraic working.
(3)
| Scheme | Marks |
|---|---|
| \(160 - 3x + 7x - 20 = 180\) or \(2(160 - 3x) + 2(7x - 20) = 360\) oe | M1 |
| e.g. \(4x = 180 - 140\) or \(-3x + 7x = 180 + 20 - 160\) or \(4x = 40\) or \(14x - 6x = 360 - 320 + 40\) oe | M1 |
| 10 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: For a correct equation
M1: For isolating the terms in \(x\) in a correct equation
A1: Dep on at least M1