4MA0 Higher January 2017 Paper 3R Q7
7 On the grid, draw the graph of \(\;y + 2x = 6\;\) for values of \(x\) from –2 to 4
(4)
| Scheme | Marks | ||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
Answer: \(y = 6 - 2x\) drawn from \(x = -2\) to \(x = 4\) | B4 | ||||||||||||||||
| (4) | |||||||||||||||||
| (4 marks) |
Notes
B4: For a correct line between \(x = -2\) and \(x = 4\)
B3: For a correct straight line segment through at least 3 of
(−2, 10) (−1, 8) (0, 6) (1, 4) (2, 2) (3, 0) (4, −2)
OR for all of (−2, 10) (−1, 8) (0, 6) (1, 4) (2, 2) (3, 0) (4, −2) plotted but not joined
B2: For at least 2 correct points plotted
B1: For at least 2 correct points stated (may be in a table) OR
for a line drawn with a negative gradient through (0, 6) OR
a line with gradient −2