4MA0 Higher January 2017 Paper 3 Q1
1 The average speed for an aeroplane flight from Dubai to London is 750 km/h.
The flight time from Dubai to London is 7 hours 18 minutes.
(a) Work out the flight distance from Dubai to London. (3)
(b) Change 750 kilometres per hour to a speed in metres per second.
Give your answer correct to the nearest whole number. (3)
Give your answer correct to the nearest whole number. (3)
| Scheme | Marks |
|---|---|
18 ÷ 60 oe or 7.3 or \(7\dfrac{18}{60}\) or \(7\dfrac{3}{10}\) or 7 × 60 + 18 (=438) | M1 |
| 750 × “7.3” oe or \(750 \times \dfrac{\text{“}438\text{”}}{60}\) oe | M1 |
| 5475 | A1 |
| (3) |
Notes
M1: for changing time to a decimal (7.3)
M1: for speed × time
(allow 750 × 7.18 or answer of 5385)
| Scheme | Marks |
|---|---|
for at least one correct operation eg. 750 × 1000, 750 ÷ 60 or \(\dfrac{1000}{60 \times 60}\) (= 0.27....) or \(\dfrac{5}{18}\) | M1 |
| \(\dfrac{750 \times 1000}{60 \times 60}\) oe | M1 |
| 208 | A1 |
| (3) | |
| (6 marks) |
Notes
M1: for one or two of ×1000, ÷60, ÷60
(can be implied by 750 000 or 12.5 or 12500 or 0.2083)
M1: complete correct method
A1: accept answers in range 208 – \(208.\dot{3}\)
Alternative mark scheme ft from (a)
| Scheme | Marks |
|---|---|
| “5475” × 1000 (=5475000) OR 7 × 60 + 18 = 438 and 438 × 60 (=26280 (sec)) | M1 |
| “5475000” ÷ 26280 | M1 |
| 208 | A1 |
Notes
M1: dep
complete correct method
A1: accept answers in range 208 – \(208.\dot{3}\)