4MA0 Higher June 2013 Paper 3R Q5
5 Show that \(\dfrac{4}{9} - \dfrac{1}{6} = \dfrac{5}{18}\)
(2)
| Scheme | Marks |
|---|---|
| \(\dfrac{8}{18} - \dfrac{3}{18}\) or \(\dfrac{8n}{18n} - \dfrac{3n}{18n}\) | M1 |
\(\dfrac{8}{18} - \dfrac{3}{18} = \dfrac{5}{18}\) or \(\dfrac{8n}{18n} - \dfrac{3n}{18n} = \dfrac{5n}{18n}\left(= \dfrac{5}{18}\right)\) | A1 |
| (2) |
Notes
M1: for 2 correct fractions with a common denominator a multiple of 9 & 6
A1: \(\dfrac{5}{18}\) coming from \(\dfrac{8}{18} - \dfrac{3}{18}\) or for final fraction equivalent to \(\dfrac{5}{18}\)