4MA0 Higher June 2013 Paper 4 Q5
5
(a) Show that \(\dfrac{7}{8} - \dfrac{5}{6} = \dfrac{1}{24}\) (2)
(b) Show that \(\dfrac{5}{8} \div \dfrac{7}{12} = 1\dfrac{1}{14}\) (2)
| Scheme | Marks |
|---|---|
| \(\dfrac{21}{24} - \dfrac{20}{24} = \dfrac{1}{24}\) | B2 |
| (2) |
Notes
B2: for both fractions written correctly with a common denominator, followed, if necessary, by cancelling to 1/24
B1 for 1 correct fraction with denominator of a multiple of 24
| Scheme | Marks |
|---|---|
| \(\dfrac{5}{8} \times \dfrac{12}{7}\) or \(\dfrac{15}{24} \div \dfrac{14}{24}\) | M1 |
| \(\dfrac{60}{56}\) | A1 |
| (2) |
Notes
M1: leaving first fraction unchanged, changing ÷ to x and inverting the second fraction or converting each fraction with a common denominator of 24 oe with ÷ sign
A1: 60/56 from the x or 15/14 from the ÷