4MA0 Higher June 2015 Paper 4R Q12
12 The straight line L is shown on the grid.
Find an equation of L.
(3)
| Scheme | Marks |
|---|---|
| (Gradient =) \(-\dfrac{3}{5}\) or \((m =)\;-\dfrac{3}{5}\) | M1 |
| M1 | |
| \(y = -\dfrac{3}{5}x + 3\) oe | A1 |
| (3) |
Notes
M1: Allow (gradient or \(m\)) = \(\dfrac{3}{5}\) or \((y =)\;-\dfrac{3}{5}x + c\) (\(c\) may be a number)
M1: Indep
\((y =)\;mx + 3\)
(\(m\) may be a number except 0)
Allow \(y\) intercept or \(c = 3\) stated
A1: oe
Eg Accept \(5y + 3x = 15\) or \(y - 3 = -\dfrac{3}{5}(x - 0)\) or \(y - 0 = -\dfrac{3}{5}(x - 5)\)
SC B2 for \(-\dfrac{3}{5}x + 3\) or \(L = -\dfrac{3}{5}x + 3\)