4MA0 Higher January 2016 Paper 4R Q19
19 Make \(g\) the subject of \(3e + 4g = 7 + 9eg\)
(3)
| Scheme | Marks |
|---|---|
| \(4g - 9eg = 7 - 3e\) or \(3e - 7 = 9eg - 4g\) | M1 |
| \(g(4 - 9e) = 7 - 3e\) or \(3e - 7 = g(9e - 4)\) | M1 |
| \(g = \dfrac{7 - 3e}{4 - 9e}\) or \(g = \dfrac{3e - 7}{9e - 4}\) | A1 |
| (3) |
Notes
M1: Correctly collecting terms in \(g\) on one side and everything else on the other.
M1: Factorising \(g(4 - 9e)\) or \(g(9e - 4)\)