4MA0 Higher June 2016 Paper 3R Q2
2
(a) Factorise fully \(2x^2 - 4x\) (2)
\(A = 2p + 3q\)
(b) Work out the value of \(p\) when \(A = 32\) and \(q = 7\) (3)
| Scheme | Marks |
|---|---|
| \(2x(x - 2)\) | B2 |
| (2) |
Notes
B2: Also award B2 for \((2x + 0)(x - 2)\)
B1 for incomplete factorisation \(2(x^2 - 2x)\) or \(x(2x - 4)\) or \(2x\) taken out as a common factor.
| Scheme | Marks |
|---|---|
| \(32 = 2p + 3 \times 7\) | M1 |
| \(2p = 32 - 3 \times 7\) or \(2p = 32 - 21\) or \(2p = 11\) or \(p = \dfrac{32 - 21}{2}\) | M1 |
| \(\dfrac{11}{2}\) | A1oe |
| (3) |
Notes
M1: Correct substitution
M1: Rearranging to make \(2p\) or \(p\) the subject (or \(-2p\) or \(-p\))