4MA0 Higher June 2016 Paper 3 Q18
18 Make \(t\) the subject of the formula \(m = \dfrac{t + 1}{t - 3}\)
(4)
| Scheme | Marks |
|---|---|
| \(m(t - 3) = t + 1\) or \(mt - 3m = t + 1\) | M1 |
| e.g. \(mt - t = 1 + 3m\) or \(t - mt = -1 - 3m\) | M1 |
| \(t(m - 1)\) or \(t(1 - m)\) | M1 |
| \(t = \dfrac{3m + 1}{m - 1}\) | A1 |
| (4) |
Notes
M1: clearing fraction
M1: for expanding bracket
AND
rearranging so that all terms in \(t\) are isolated on one side of a correct equation
M1: take \(t\) out as a common factor (in an equation)
A1: or \(t = \dfrac{-3m - 1}{1 - m}\) oe