4MA0 Foundation January 2015 Paper 2R Q19
19
Diagram NOT accurately drawn
\(ABCD\) is a parallelogram.
Angle \(DCB = 110^\circ\)
\(X\) is the point on \(DC\) such that \(AX\) bisects the angle \(DAB\).
Calculate the size of angle \(AXC\).
(4)
| Scheme | Marks |
|---|---|
| Angle DAB = 110 | B1 |
| Angle BAX =110 ÷ 2 (= 55) or Angle DAX =110 ÷ 2 (= 55) or Angle AXD = 55 | M1 |
| Angle AXD = 55 or Angle CBA = 180 – 110 (=70) or Angle ADC = 180 – 110 (=70) | M1 |
| 125 | A1 |
| (4) | |
| (4 marks) |
Notes
B1: can be implied by angle \(DAX\) = angle \(BAX = 55^\circ\)