4MA0 Higher January 2014 Paper 4R Q10
10

Diagram NOT accurately drawn
The diagram shows the positions of a yacht \(Y\), a ship \(S\) and a beacon \(B\).
The bearing of \(B\) from \(Y\) is 228°
(a) Find the bearing of \(Y\) from \(B\). (2)
The bearing of \(S\) from \(Y\) is 118°
(b) Find the size of the angle \(BYS\). (1)
(c) Given also that \(BY = SY\), find the bearing of \(S\) from \(B\). (2)
| Scheme | Marks |
|---|---|
| 228 – 180 (=48) or 360 – 228 (= 132) then 180 – 132 | M1 |
| 048 | A1 |
| (2) |
Notes
M1: Can be marked on diagram.
i.e Full method leading to correct answer.
A1: Accept 48
| Scheme | Marks |
|---|---|
| 110 | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| 228 – 118 (= 110) (180 – “110”) ÷ 2 (= 35) “48” + “35” | M1ft |
| 083 | A1 |
| (2) | |
| (5 marks) |
Notes
M1ft: bearing from (a) + 35
A1: accept 83