4MA0 Foundation January 2018 Paper 1R Q12
12

Diagram NOT accurately drawn
\(APD\), \(BPE\) and \(CPF\) are straight lines.
Angle \(CPD = 70^\circ\)
Angle \(APB\) = angle \(BPC = x^\circ\)
(a) Find the size of angle \(FPA\). (1)
(b) Work out the value of \(x\). (2)
| Scheme | Marks |
|---|---|
| 70 | B1 |
| (1) |
Notes
B1: ft ‘55’
| Scheme | Marks |
|---|---|
| (180 − 70) ÷ 2 or (360 − 2 × 70) ÷ 4 | M1 |
| 55 | A1 |
| (2) |
Notes
A1: allow ft on their \(FPA\)