4MA0 Higher January 2018 Paper 4R Q18
18 \(ABCD\) is a rectangle.
The perimeter of \(ABCD\) is 64 cm, correct to the nearest centimetre.
\(AB = 17\) cm, correct to the nearest centimetre.
Calculate the lower bound of the length of \(AD\).
Show your working clearly.
(3)
| Scheme | Marks |
|---|---|
| 17.5, \(17.4\dot{9}\), 16.5, 63.5 or 64.5 or \(64.4\dot{9}\) | B1 |
| \(\dfrac{\text{LB} - 2 \times \text{UB}}{2}\) | M1 |
| 14.25 oe | A1 |
| (3) | |
| (3 marks) |
Notes
B1: For any correct LB or UB
M1: \(63.5 \leqslant \text{LB} \lt 64\)
\(17 \lt \text{UB} \leqslant 17.5\)
A1: From correct working