4MA0 Higher January 2018 Paper 3 Q5
5
Show clear algebraic working. (3)

| Scheme | Marks |
|---|---|
| \(3 - 6y = 2y - 7\) or \(1 - 2y = \dfrac{2y}{3} - \dfrac{7}{3}\) | M1 |
| e.g. \(-6y - 2y = -7 - 3\) or \(3 + 7 = 2y + 6y\) or \(-8y = -10\) or \(8y = 10\) | M1 |
| 1.25 oe | A1 |
| (3) |
Notes
M1: for multiplying out brackets in a correct equation or dividing all terms by 3
M1: for isolating the terms in \(y\)
ft from \(3 - 2y = 2y - 7\) or \(1 - 6y = 2y - 7\)
A1: dep on M1 awarded
| Scheme | Marks |
|---|---|
| \(-3 \lt x \leqslant 4\) | B2 |
| (2) |
Notes
B2: also accept \(x > -3\) and \(x \leqslant 4\)
or \(4 \geqslant x > -3\)
If not B2 then award
B1 for a double-ended inequality which is correct at one end (ignore the other end)
eg. \(-3 \lt x \lt 4\), \(-3 \leqslant x \leqslant 4\), \(-3 \lt x > 4\)
or for an answer of \(x > -3\) oe or \(x \leqslant 4\) oe
or the wrong variable in an otherwise correct inequality eg. \(-3 \lt y \leqslant 4\)
SC : Award B1 for \(-3 \leqslant x \lt 4\)
| Scheme | Marks |
|---|---|
| e.g. \(2m \geqslant 8 - 13\) | M1 |
| \(m \geqslant -2.5\) oe | A1 |
| (2) |
Notes
M1: for isolating terms in \(m\) (in an equation or inequality)
e.g. \(2m \geqslant -5\)
or −2.5 oe
A1: must be an inequality