D1 January 2011 Q5
5.

[The total weight of the network is 31.6 km]
Figure 5 models a network of roads. The road markings on these roads are to be renewed. The number on each arc represents the length, in km, of that road. In order to renew the road markings, each road must be traversed at least once.
The machine that will be used to renew the road markings can only be delivered to D. It will start at D, but it may finish at any vertex.
Each road must still be traversed at least once.
| Scheme | Marks |
|---|---|
| AD + FI = 4.5 + 5.3 = 9.8 | M1 A1 |
| AF + DI = 5.8 + 3.9 = 9.7 smallest | A1 |
| AI + DF = 5.9 + 5.1 = 11.0 | A1 |
| e.g. ABDGIGDEIHFEACFEA | A1 |
| (5) |
Notes
1M1: Three pairings of their four odd nodes
1A1: one row correct
2A1: two rows correct
3A1: all correct
4A1: Any correct route (17 nodes)
| Scheme | Marks |
|---|---|
| Roads AE, EF (or AEF), DG and GI (or DGI) should be repeated. | B1 |
| Length is 31.6 + 9.7 = 41.3 km | M1A1ft |
| (3) |
Notes
1B1: correct arcs identified
1M1: 31.6 + ft their least, from a choice of at least two.
1A1: ft has correctly their plausible least (from a choice of at least two) to 31.6.
| Scheme | Marks |
|---|---|
| We now only have to repeat one pair of odd vertices, one of which can not be D. (FI = 5.3, AF = 5.8 and AI = 5.9) | M1 |
| FI gives the smallest of the three so choose to repeat FI (FHI) | A1 |
| The machine should be collected from A. | DA1 |
| (3) | |
| (11 marks) |
Notes
1M1: Identifies need to repeat one pairing, not including D (maybe implicit) or listing of potential repeats.
1A1: Identifies FI as least.
2DA1: dependent on their identifying FI as repeat