D1 June 2010 Q4
4.

[The total weight of the network is 73.3 km]
Figure 2 models a network of tunnels that have to be inspected. The number on each arc represents the length, in km, of that tunnel.
Malcolm needs to travel through each tunnel at least once and wishes to minimise the length of his inspection route.
He must start and finish at A.
State the length of your route. (3)
A new tunnel, CG, is under construction. It will be 10 km long.
Malcolm will have to include the new tunnel in his inspection route.
Justify your answer. (2)
| Scheme | Marks |
|---|---|
| BC + EG = 10.4 + 10.1 = 20.5 smallest | M1 A1 |
| BE + CG = 8.3 + 16.1 = 24.4 | A1 |
| BG + CE = 14.9 + 11.9 = 26.8 | A1 |
| So repeat tunnels BA, AC and EG | A1 |
| (5) |
Notes
1M1: Three pairings of their four odd nodes
1A1: one row correct
2A1: two rows correct
3A1: all correct
4A1: correct arcs identified
| Scheme | Marks |
|---|---|
| Any route e.g. ACFGDCABDEGEBA | B1 |
| Length = 73.3 + their 20.5 = 93.8km | M1 A1 |
| (3) |
Notes
1B1: Any correct route (14 nodes)
1M1: 73.3 + ft their least, from a choice of at least two.
1A1: cao
| Scheme | Marks |
|---|---|
| The new tunnel would make C and G even. So only BE would need to be repeated. | B1 |
| Extra distance would be 10 + 8.3 = 18.3 < 20.5 [91.6 < 93.8] So it would decrease the total distance. | DB1 |
| (2) | |
| (10 marks) |
Notes
1B1: A correct explanation, referring to BE and relevant numbers (8.3, 12.2, 2.2, 18.3,81.3, 91.6) maybe confused, incomplete or lack conclusion –bod gets B1
2B1D: A correct, clear explanation all there + conclusion (ft on their numbers.)