M1 June 2018 Q3
3.

A wooden beam \(AB\), of mass 150 kg and length 9 m, rests in a horizontal position supported by two vertical ropes. The ropes are attached to the beam at \(C\) and \(D\), where \(AC = 1.5\) m and \(BD = 3.5\) m. A gymnast of mass 60 kg stands on the beam at the point \(P\), where \(AP = 3\) m, as shown in Figure 2. The beam remains horizontal and in equilibrium.
By modelling the gymnast as a particle, the beam as a uniform rod and the ropes as light inextensible strings,
The gymnast at \(P\) remains on the beam at \(P\) and another gymnast, who is also modelled as a particle, stands on the beam at \(B\). The beam remains horizontal and in equilibrium. The mass of the gymnast at \(B\) is the largest possible for which the beam remains horizontal and in equilibrium.
| Scheme | Marks |
|---|---|
| \(M(D),\ \ (150g \times 1) + (60g \times 2.5) = T_C \times 4\) | M1 A1 |
| \(T_C = 75g\) or 735 N or 740 N Allow omission of N | A1 |
| (3) |
Notes
M1 for a complete method to find \(T_C\) (M0 if they assume \(T_C = T_D\))
i.e. for producing an equation in \(T_C\) only. Each equation used must have correct no. of terms and be dimensionally correct.
First A1 for correct equation.
Second A1 for any of the 3 possible answers
Other possible equations:
\((\uparrow),\ T_C + T_D = 60g + 150g\)
\(M(A),\ \ (150g \times 4.5) + (60g \times 3) = (T_C \times 1.5) + (T_D \times 5.5)\)
\(M(C),\ \ (150g \times 3) + (60g \times 1.5) = T_D \times 4\)
\(M(B),\ \ (150g \times 4.5) + (60g \times 6) = (T_C \times 7.5) + (T_D \times 3.5)\)
\(M(G),\ \ (T_D \times 1) + (60g \times 1.5) = T_C \times 3\)
| Scheme | Marks |
|---|---|
| \(M(B),\ \ (150g \times 4.5) + (60g \times 6) = T_D \times 3.5\) | M1 A2 |
| \(T_D = 2900\) N or \(\dfrac{2070g}{7}\) Allow omission of N | A1 |
| (4) | |
| (7 marks) |
Notes
N.B. (M0 if \(T_C\) is never equated to 0)
M1 for a complete method to obtain an equation in \(T_D\) only.
If they use more than one equation, each equation used must have correct no. of terms and be dimensionally correct.
First and second A1 for a correct equation in \(T_D\) only. A1A0 if one error. Consistent omission of \(g\) is one error except in \(M(D)\) where it’s not an error.
Third A1 for either answer
Other possible equations:
\((\uparrow),\ T_D = 60g + 150g + Mg\)
\(M(A),\ \ (150g \times 4.5) + (60g \times 3) + 9Mg = T_D \times 5.5\)
\(M(C),\ \ (150g \times 3) + (60g \times 1.5) + 7.5Mg = T_D \times 4\)
\(M(D),\ \ (150g \times 1) + (60g \times 2.5) = 3.5Mg\)
\(M(G),\ \ (T_D \times 1) + (60g \times 1.5) = 4.5Mg\)