S3 June 2017 Q4
4. A psychologist carries out a survey of the perceived body weight of 150 randomly chosen people. He asks them if they think they are underweight, about right or overweight. His results are summarised in the table below.
| Underweight | About right | Overweight | |
|---|---|---|---|
| Male | 20 | 22 | 30 |
| Female | 16 | 28 | 34 |
The psychologist calculates two of the expected frequencies, to 2 decimal places, for a test of independence between perceived body weight and gender. These results are shown in the table below.
| Underweight | About right | Overweight | |
|---|---|---|---|
| Male | 17.28 | ||
| Female | 18.72 |
The psychologist now combines the male and female data to test whether or not body weight types are chosen equally.
| Scheme | Marks |
|---|---|
| \(\dfrac{72 \times 50}{150} = 24,\ \dfrac{78 \times 50}{150} = 26\) | M1 |
| \(\dfrac{72 \times 64}{150} = 30.72,\ \dfrac{78 \times 64}{150} = 33.28\) | A1 |
| (2) |
Notes
M1 For one correct \(\frac{\text{Row Total} \times \text{Column Total}}{\text{Grand Total}}\); can be implied by correct answers.
A1 24, 26, 30.72, 33.28 only.
| Scheme | Marks | ||||||||||||||||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| \(\mathrm{H}_0 :\) Perceived (body) weight is independent of gender (no association) \(\mathrm{H}_1 :\) Perceived (body) weight is not independent of gender (association) | B1 | ||||||||||||||||||||||||||||||||
| M1A1 | ||||||||||||||||||||||||||||||||
| \(\displaystyle\sum \frac{(O-E)^2}{E}\) or \(\displaystyle\sum \frac{O^2}{E} - 150 = 1.18\) | A1 | ||||||||||||||||||||||||||||||||
| \(\nu = (3-1)(2-1) = 2,\ \chi^2_2(10\%) = 4.605\) | B1B1ft | ||||||||||||||||||||||||||||||||
| (Accept \(\mathrm{H}_0\)) Perceived (body) weight is independent of gender (no association) | A1ft | ||||||||||||||||||||||||||||||||
| (7) |
Notes
B1 Both hypotheses required. Must mention “Perceived”, “weight” and “gender” at least once.
Use of “relationship” or “correlation” or “connection” or “link” award B0.
M1 for at least 2 correct terms (as in 3rd or 4th column) or correct expressions.
A1 for all correct. Accept 2sf accuracy. Allow truncation e.g. 1.17…
A1 Awrt 1.18-1.19
B1B1ft 2 can be implied by 4.605 seen
A1ft A correct comment in context - must mention “weight” and “gender”. Condone “relationship” or “connection” here but not “correlation”.
Follow through from their test stat and cv, but hypotheses must be correct.
| Scheme | Marks | ||||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| B1 M1A1 | ||||||||||||||||||||
| \(\displaystyle\sum \frac{(O-E)^2}{E}\) or \(\displaystyle\sum \frac{O^2}{E} - 150 = 7.84\) | A1 | ||||||||||||||||||||
| \(\nu = 2,\ \chi^2_2(2.5\%) = 7.378\) | A1 | ||||||||||||||||||||
| (5) | |||||||||||||||||||||
| (14 marks) |
Notes
B1 for \(E_i = 50\), could be implied.
M1 for combining values and for attempting \(\dfrac{(O-E)^2}{E}\) or \(\dfrac{O^2}{E}\) with at least 2 correct expressions or values.
A1 for all correct, can be implied by correct answer below.
A1 Awrt 7.84
A1 0.025 or 2.5%