M2 January 2006 Q7
7.

The object of a game is to throw a ball \(B\) from a point \(A\) to hit a target \(T\) which is placed at the top of a vertical pole, as shown in Figure 3. The point \(A\) is 1 m above horizontal ground and the height of the pole is 2 m. The pole is at a horizontal distance of 10 m from \(A\). The ball \(B\) is projected from \(A\) with a speed of 11 m s\(^{-1}\) at an angle of elevation of 30\(^\circ\). The ball hits the pole at the point \(C\). The ball \(B\) and the target \(T\) are modelled as particles.
The ball is thrown again from \(A\). The speed of projection of \(B\) is increased to \(V\) m s\(^{-1}\), the angle of elevation remaining 30\(^\circ\). This time \(B\) hits \(T\).
| Scheme | Marks |
|---|---|
| \(u_x = 11\cos 30^\circ\) | B1 |
| \(\rightarrow\) \(11\cos 30^\circ \times t = 10\ \ \Rightarrow\ \ t = 1.05\) (s) cao | M1 A1 |
| (3) |
| Scheme | Marks |
|---|---|
| \(s = \underline{11\sin 30^\circ} \times t - 4.9t^2 \approx 0.37\) | B1 M1 A1 |
| \((2 - 1) - 0.37 = 0.63\) (m) | A1 |
| (4) |
| Scheme | Marks |
|---|---|
| \(V\cos 30^\circ \times t = 10\) \(\left(t = \dfrac{10}{V\cos 30^\circ}\right)\) | M1 A1 |
| \(s = V\sin 30^\circ \times \dfrac{10}{V\cos 30^\circ} - \dfrac{4.9 \times 100}{V^2\cos^2 30^\circ} = 1\) | M1 A1 |
| \(V^2 = 136.86\) | M1 |
| \(V \approx 12\) accept 11.7 | A1 |
| (6) |
Notes
(Corrected from the printed mark scheme: the denominator is printed as \(V^2\cos^2\theta\).)
| Scheme | Marks |
|---|---|
| \(B\) and/or \(T\) are not particles (They have extension giving a range of answers) | B1 |
| (1) | |
| (14 marks) |