M2 January 2006 Q3
3. A car of mass 1000 kg is moving along a straight horizontal road. The resistance to motion is modelled as a constant force of magnitude \(R\) newtons. The engine of the car is working at a rate of 12 kW. When the car is moving with speed 15 m s\(^{-1}\), the acceleration of the car is 0.2 m s\(^{-2}\).
The car now moves with constant speed \(U\) m s\(^{-1}\) downhill on a straight road inclined at \(\theta\) to the horizontal, where \(\sin\theta = \tfrac{1}{40}\). The engine of the car is now working at a rate of 7 kW. The resistance to motion from non-gravitational forces remains of magnitude \(R\) newtons.
| Scheme | Marks |
|---|---|
| \(T_r = \dfrac{12000}{15}\ \ (= 800)\) | M1 |
| N2L \(800 - R = 1000 \times 0.2\) ft their 800 | M1 A1ft |
| \(R = 600\ \ *\) cso | A1 |
| (4) |
| Scheme | Marks |
|---|---|
| \(1000g \times \dfrac{1}{40} + T_r = R\) | M1 A1 |
| \(T_r = \dfrac{7000}{U}\) | M1 |
| \(U \approx 20\) accept 19.7 | M1 A1 |
| (5) | |
| (9 marks) |
Notes
(The question paper prints this part as (c); there is no part (b) on the paper.)