S2 June 2012 Q3
3.
A machine which manufactures bolts is known to produce 3% defective bolts. The machine breaks down and a new machine is installed. A random sample of 200 bolts is taken from those produced by the new machine and 12 bolts were defective.
| Scheme | Marks |
|---|---|
| \(n\) – large/high/big/ \(n \gt 50\) | B1 |
| \(p\) – small/close to 0 / \(p \lt 0.2\) | B1 |
| (2) |
| Scheme | Marks |
|---|---|
| \(\mathrm{H}_0 : p = 0.03 \qquad \mathrm{H}_1 : p \gt 0.03\) | B1,B1 |
| Po(6) | B1 |
| \(\mathrm{P}(X \geqslant 12) = 1 - \mathrm{P}(X \leqslant 11)\) or \(\mathrm{P}(X \leqslant 10) = 0.9574\) | M1 |
| \(= 1 - 0.9799\) \(\mathrm{P}(X \geqslant 11) = 0.0426\) | |
| \(= 0.0201\) CR \(X \geqslant 11\) | A1 |
| \((0.0201 \lt 0.05)\) Reject \(\mathrm{H}_0\) or Significant or 12 lies in the Critical region. | M1 dep. |
| There is evidence that the proportion of defective bolts has increased. | A1 ft |
| (7) | |
| (9 marks) |
Notes
1st B1 for \(\mathrm{H}_0 : p = 0.03\)
2nd B1 for \(\mathrm{H}_1 : p \gt 0.03\)
SC If both hypotheses are correct but a different letter to \(p\) is used they get B1 B0
Also allow B1 B0 for \(\mathrm{H}_0 : \lambda = 6\) and \(\mathrm{H}_1 : \lambda \gt 6\)
B1 writing or using Po(6)
One tail
1st M1 for writing or using \(1 - \mathrm{P}(X \leqslant 11)\) or giving \(\mathrm{P}(X \leqslant 10) = 0.9574\) or giving \(\mathrm{P}(X \geqslant 11) = 0.0426\). May be implied by correct CR or probability = 0.0201
1st A1 for 0.0201 or CR \(X \geqslant 11\)/ \(X \gt 10\). NB \(\mathrm{P}(X \leqslant 11) = 0.9799\) on its own scores M1A1
2nd M1 dependent on the 1st M1 being awarded. For a correct statement based on the table below. Do not allow non-contextual conflicting statements eg “significant” and “accept \(\mathrm{H}_0\)”. Ignore comparisons.
2nd A1 ft for a correct contextualised statement. NB A correct contextual statement on its own scores M1A1.
| \(0.05 \lt p \lt 0.95\) | \(p \lt 0.05\) or \(p \gt 0.95\) | |
| 2nd M1 | not significant/ accept \(\mathrm{H}_0\)/ Not in CR | significant/ reject \(\mathrm{H}_0\)/ In CR |
| 2nd A1 | The proportion/number/amount/percentage oe of defective bolts has not increased/is not higher/oe | The proportion/number/amount/percentage oe of defective bolts has increased/is higher/oe |
Two tail
1st M1 for writing or using \(1 - \mathrm{P}(X \leqslant 11)\) or giving \(\mathrm{P}(X \geqslant 12) = 0.0201\) or giving \(\mathrm{P}(X \leqslant 11) = 0.9799\). May be implied by correct CR or probability = 0.0201
1st A1 for 0.0201 or CR \(X \geqslant 12\)/ \(X \gt 11\). NB \(\mathrm{P}(X \leqslant 11) = 0.9799\) on its own scores M1A1
2nd M1 dependent on the 1st M1 being awarded. For a correct statement based on the table below. Do not allow non-contextual conflicting statements eg “significant” and “accept \(\mathrm{H}_0\)”. Ignore comparisons.
2nd A1 ft for a correct contextualised statement. NB A correct contextual statement on its own scores M1A1.
| \(0.025 \lt p \lt 0.975\) | \(p \lt 0.025\) or \(p \gt 0.975\) | |
| 2nd M1 | not significant/ accept \(\mathrm{H}_0\)/ Not in CR | significant/ reject \(\mathrm{H}_0\)/ In CR |
| 2nd A1 | The proportion/number/amount/percentage oe of defective bolts has not increased/is not higher/oe | The proportion/number/amount/percentage oe of defective bolts has increased/is higher/oe |
Use of N(6,5.82) May get B1 B1 B0 M1 (must use 11.5)A0 M1dep A1 ft