June 2019 Paper 1 Q5
5 Solve \(\quad \sqrt[3]{\left(2\sqrt{x} - 10\right)} = 2\) [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(2\sqrt{x} - 10 = 2^3\) or \(2\sqrt{x} - 10 = 8\) or \(2\sqrt{x} = 18\) | M1 | |
| \(\sqrt{x} = \dfrac{2^3+10}{2}\) or \(\sqrt{x} = \dfrac{8+10}{2}\) or \(\sqrt{x} = 9\) or \(4x = 18^2\) or \(x = 9^2\) | M1dep | |
| \(x = 81\) | A1 | \(\pm 81\) scores A0 |