Foundation June 2022 Paper 1 Q17
17 Solve \(2x + 5 \geqslant 11\).
Show your solution on the number line.
[4]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(x \geqslant 3\) | 4 | B2 for \(x \geqslant 3\) or M1 for \(2x \geqslant 11 - 5\) or better or \(x + 2.5 \geqslant 5.5\) or better | Solution to inequality Allow M1 for this expression with other inequality symbols or equals sign or [x =] 3 as solution (can be implied by mark/circle on the diagram) or trials leading to selection of 3 or final correct trial using 3 |
AND | AND B2FT for their inequality correctly shown or B1FT for correctly placed circle for their \(x \geqslant 3\) but with hollow circle and correct arrow or for filled circle with incorrect arrow | Displaying the solution: Display must show an inequality that fits on the number line for FT Mark to candidate’s advantage either \(x \geqslant 3\) or their inequality Accept an arrow of any length or a line reaching 9 If no solution to inequality seen: Filled circle at 3 arrow to right M1B2 Filled circle at 3 arrow to left M1B1 Hollow circle at 3 arrow to right M1B1 Hollow circle at 3 arrow to left M1B0 Mark at 3 no line or arrow M1B0 Circle and/or arrow at other than 3 M0B0 | |