Foundation June 2023 Paper 1 Q6
6 Here is a function.
(a) Find the input when the output is 87. [2]
(b) The input is \(x\) and the output is \(y\).
Write an equation for \(y\) in terms of \(x\). [2]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 20 final answer | 2 | M1 for \(87 - 7\) implied by 80 or their \((87 - 7) \div 4\) or 20 x 4 = 80 + 7 = 87 oe | |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(y = 4x + 7\) final answer | 2 | M1 for final answer \(4x + 7\) or \(y = 4x - 7\) or \(y = kx + 7\) \((k \ne 0)\) or \(y = 4x + c\) where \(c \gt 0\) final answer or \(x = 4y + 7\) If 0 scored SC1 for \(x = \dfrac{y - 7}{4}\) final answer | Accept throughout \(y\) on right e.g. \(4x + 7 = y\) Accept throughout \(x\) x 4 or \(x\) 4 or x \(xk\) but not \(x^4\) Accept \(y = 4(x + c)\) where \(c \gt 0\) \(4x + 7y\) scores 0 \(x = 4x + 7\) scores 0 Do not accept arrows e.g. \(4 \rightarrow xx \rightarrow 7 \rightarrow y\) |