Higher November 2019 Paper 5 Q5
5 Solve.
\(6x - 10 = 4x + 1\) [3]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 5.5 oe | 3 | M1 for correct first step e.g. \(6x - 4x - 10 = 1\) M1 for \(6x - 4x = 1 + 10\) FT their first step or FT their \(ax = b\) to \(x = \frac{b}{a}\) | isw \(\frac{11}{2}\) converted to decimal Embedded answer scores M2 max If not shown, M1 implied by \(\pm 2x = b\) or \(ax = \pm 11\) e.g. M1 for \(2x = -9\) leading to \(x = -\frac{9}{2}\) oe |