Higher November 2019 Paper 4 Q14
14 The diagram shows a circle with centre (0, 0) and a tangent at the point (−12, 16).
Not to scale
The tangent crosses the \(y\)-axis at the point (0, \(p\)).
Find the value of \(p\). [5]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 25 | 5 | M1 for \(m_1 = \frac{16}{-12}\) oe M1 for \(m_2 = \frac{-1}{\textit{their}\ m_1}\) or \(\frac{12}{16}\) oe M1 for \(y = (\textit{their}\ \frac{12}{16})x + p\) M1 for substituting (-12,16) into their equation accept any correct method | gradient of radius gradient of tangent |