Higher November 2020 Paper 5 Q12
12 The price, £\(P\), of a car is £20 000 in 2019.
The price is expected to decrease by 5% each year after 2019.
(a) Jasmine says
This means the price in 2021 is expected to be £18 000.
She is incorrect.
Explain her error and work out the correct answer. [4]
(b)
(i) Write a formula for \(P\) in terms of \(n\), where \(n\) is the number of years after 2019. [2]
(ii) Circle the graph that best represents the price, £\(P\), of the car \(n\) years after 2019.
[1]

| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| She has reduced the price by 10% oe | B1 | e.g. She has decreased by 1000 each year She took 10%/ found 90% [of 20 000] See AG | |
| 18 050 | B3 | M2 for 20 000 × 0.952 oe or B1 for 1000 or 19 000 seen | |
Appendix: Exemplar responses Q12(a)
| Response | Mark |
|---|---|
| She kept decreasing by 5% of 20000 | 1 |
| She took off the same amount of interest as the first year | 1 |
| She should not decrease by the same amount each year [ it should be different] | 1 |
| She did simple interest rather than compound interest | 1 |
| She is decreasing by the same amount each year | 1 |
| She did not do 5% of the second year, just 5% of the first year | 1 |
| She took £1000 off each year | 1 |
| She should have done 5% for each year | 1 |
| She did not decrease the result of the first price (she did by 1000) | 0 |
| She has just decreased it by 5% each year | 0 |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| (i) \(20\,000 \times 0.95^n\) oe | 2 | M1 for 0.95 oe or for 20 000 × \(k^n\) (\(k \ne 0\)) | |
| (ii) Second graph indicated | 1 | ||