Foundation November 2019 Paper 3 Q12
12
(a) Find the value of
(i) \(\sqrt[3]{216}\), [1]
(ii) \(2^8\). [1]
(b) The cube of 3 is added to the square root of 7.
Put a ring around the correct statement.
- \(\sqrt[3]{3} + 7^2\)
- \(3^3 + 7^2\)
- \(3^3 + \sqrt{7}\)
- \(\sqrt[3]{3} + \sqrt{7}\)
[1]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| (i) 6 | 1 | ||
| (ii) 256 | 1 | ||
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(3^3 + \sqrt{7}\) final answer | 1 | Accept clear indication | |