Foundation November 2018 Paper 3 Q21
21 Here is a right-angled triangle.
Use trigonometry to work out the value of \(x\). [3]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 3.488 to 3.489 or 3.49 or 3.5 | 3 | M2 for 10.2 \(\times\) sin20 or any complete correct method or M1 for \(\sin 20 = \dfrac{x}{10.2}\) | Cos70 \(\times\) 10.2 or 10.2 \(\times\) cos 20 and \(\sqrt{10.2^2 - (10.2 \times \cos 20)^2}\) Allow 10.2 \(\times\) cos 20 with attempt at Pythagoras for M1 |