Foundation June 2018 Paper 3 Q19
19 Asha worked out \(\dfrac{326.8 \times (6.94 - 3.4)}{59.4}\).
She got an answer of 19.5, correct to 3 significant figures.
Write each number correct to 1 significant figure to decide if Asha’s answer is reasonable. [3]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(\dfrac{300 \times (7 - 3)}{60} = 20\) AND it is close to 19.5 oe or 19.5 rounds to 20 oe or [Asha’s estimate] is reasonable | 3 | B2 for 300, 7, 3 and 60 seen or B1 for two of 300, 7, 3 and 60 seen or 300, 4 and 60 seen or 300.0, 7.0, 3.0. 60.0 AND B1dep for result 20 and correct conclusion following B1 or B2 | Actual answer 19.475959...(may be rounded) scores 0 Accept “Yes” or “She’s right” or “It is” or equivalent comment |