Foundation June 2017 Paper 1 Q14
14
(a) Write 543 000 in standard form. [1]
(b) Write \(6.3 \times 10^{-2}\) as an ordinary number. [1]
(c) Pierre is given this question.
| Work out. 61 000 \(\times\) 4000 Give your answer in standard form. |
Pierre’s answer is \(24.4 \times 10^7\).
Is Pierre correct?
Explain your answer. [1]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(5.43 \times 10^5\) | 1 | ||
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| [0].063 | 1 | ||
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| No, it isn’t in standard form, e.g it should be \(2.4[4] \times 10^8\) | 1 | See appendix | |
Appendix
Exemplar responses for Q14c
| Response | Mark |
|---|---|
| He is not correct because the decimal point was moved to make a number bigger than 10 | 1 bod |
| No because the number has to be between 1 and 10 | 1 bod |
| No because the number has to be between 1 and 9, it should be \(2.44 \times 10^8\) | 1 bod |
| No because the decimal has to be lower than 10 | 1 bod |
| No only 1 number should be before decimal point and he wrote 2 | 1 |
| It should be \(2.44 \times 10^8\) | 1 |
| Standard form is \(2.44 \times 10^8\) | 1 |
| No because the number has to be between 1 and 9 | 0 |
| Pierre is not correct as it is \(2.44 \times 10^7\) and he got \(24.4 \times 10^7\) | 0 |
| No the power should be 8 | 0 |