Higher January 2019 Paper 1 Q1
1
(a) Factorise fully \(4p + 6pq\) (2)
(b) Expand and simplify \((e + 3)(e - 5)\) (2)
(c) Solve \(y = \dfrac{2y + 1}{5}\)
Show clear algebraic working. (3)
Show clear algebraic working. (3)
| Scheme | Marks |
|---|---|
| \(2p(2 + 3q)\) | B2 |
| (2) |
Notes
B2: If not B2 then award B1 for \(2(2p + 3pq)\) or \(p(4 + 6q)\) or \(2p\)(a two term expression) or \(x(2 + 3q)\) where \(x \ne 2p\)
| Scheme | Marks |
|---|---|
| \(e^2 + 3e - 5e - 15\) | M1 |
| \(e^2 - 2e - 15\) | A1 |
| (2) |
Notes
M1: for 3 correct terms or for 4 correct terms ignoring signs or \(e^2 - 2e + k\) for non-zero \(k\) or \(\ldots - 2e - 15\)
| Scheme | Marks |
|---|---|
| \(5y = 2y + 1\) or \(y = \dfrac{2y}{5} + \dfrac{1}{5}\) | M1 |
| E.g. \(5y - 2y = 1\) or \(3y = 1\) or \(3y - 1 = 0\) or \(\dfrac{3y}{5} = \dfrac{1}{5}\) | M1 |
Working required Answer: \(\dfrac{1}{3}\) oe | A1 |
| (3) | |
| (7 marks) |
Notes
M1: for a correct first step
M1: for collecting terms in \(y\) in a correct equation
A1: dep on at least M1 for \(\dfrac{1}{3}\) oe e.g. \(0.\dot{3}\), 0.3333…